‘Swapping Nodes in a Linked List (Medium)`
📌 Problem
https://leetcode.com/problems/swapping-nodes-in-a-linked-list/
📌 Answer
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/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode swapNodes(ListNode head, int k) {
ListNode fast = head;
ListNode slow = head;
ListNode first = head, second = head;
// Put fast (k-1) nodes after slow
for (int i = 1; i < k; i++)
fast = fast.next;
// Save the node for swapping
first = fast;
// Move until the end of the list
while (fast.next != null) {
slow = slow.next;
fast = fast.next;
}
// Save the second node for swapping
// Note that the pointer second isn't necessary: we could use slow for swapping as well
// However, having second improves readability
second = slow;
// Swap values
int temp = first.val;
first.val = second.val;
second.val = temp;
return head;
}
}
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