‘Sort List (Medium)`
📌 Problem
https://leetcode.com/problems/sort-list/
📌 Answer
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/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode sortList(ListNode head) {
//bottom case
if (head == null) {
return head;
}
if (head.next == null) {
return head;
}
//p1 move 1 step every time, p2 move 2 step every time, pre record node before p1
ListNode p1 = head;
ListNode p2 = head;
ListNode pre = head;
while (p2 != null && p2.next != null) {
pre = p1;
p1 = p1.next;
p2 = p2.next.next;
}
//change pre next to null, make two sub list(head to pre, p1 to p2)
pre.next = null;
//handle those two sub list
ListNode h1 = sortList(head);
ListNode h2 = sortList(p1);
return merge(h1, h2);
}
//merge two sorted list, return result head
public ListNode merge(ListNode h1, ListNode h2) {
if (h1 == null) {
return h2;
}
if (h2 == null) {
return h1;
}
if (h1.val < h2.val) {
h1.next = merge(h1.next, h2);
return h1;
}
else {
h2.next = merge(h1, h2.next);
return h2;
}
}
}
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class Solution {
public ListNode sortList(ListNode head) {
ListNode temp=head;
int count=0;
while(temp!=null){
count++;
temp=temp.next;
}
temp=head;
int a[]=new int[count];
count=0;
while(temp!=null){
a[count++]=temp.val;
temp=temp.next;
}
temp=head;
Arrays.sort(a);
int k=0;
while(temp!=null){
temp.val=a[k++];
temp=temp.next;
}
return head;
}
}
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