‘Remove Nth Node From End of List’ in LeetCode (Medium)
📌 Problem
https://leetcode.com/problems/remove-nth-node-from-end-of-list/
📌 Answer
Two-Pointer
The point
- For a singly linked list, used two pointer ‘fast’, ‘slow’
The time and space complexity is quite good.
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class Solution {
public ListNode removeNthFromEnd(ListNode head, int n) {
ListNode start = new ListNode(0);
// two pointer
ListNode slow = start, fast = start;
start.next = head;
for (int i = 1; i <= n + 1; i++) {
fast = fast.next;
}
while (fast != null) {
slow = slow.next;
fast = fast.next;
}
slow.next = slow.next.next;
return start.next;
}
}
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
/**
[Question]
- remove the nth node from the end of the list
- return its head.
[Condition]
- The number of nodes in the list is sz.
**/
The source : https://leetcode.com/problems/remove-nth-node-from-end-of-list/discuss/589304/CLEAR-JAVA-SOLUTION-WITH-DETAILED-EXPLANATION! And ⭐️ it’s the best explanation
I’m not good at singly linked list….
Let’s search it.
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